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位置:編程語(yǔ)言培訓(xùn)資訊 > VB培訓(xùn)資訊 > 設(shè)計(jì)猜數(shù)游戲項(xiàng)目目的,VB程序設(shè)計(jì)中怎么設(shè)計(jì)猜數(shù)游戲???!!!

設(shè)計(jì)猜數(shù)游戲項(xiàng)目目的,VB程序設(shè)計(jì)中怎么設(shè)計(jì)猜數(shù)游戲???!!!

日期:2021-12-26 17:52:28     瀏覽:453    來源:游戲設(shè)計(jì)交流中心
核心提示:科技時(shí)代到來,優(yōu)異也隨之而來,我們會(huì)去關(guān)注C語(yǔ)言程序設(shè)計(jì)猜數(shù)游戲,VB程序設(shè)計(jì)中怎么設(shè)計(jì)猜數(shù)游戲???!!!,c語(yǔ)言課程設(shè)計(jì)-猜數(shù)游戲,設(shè)計(jì)一個(gè)猜數(shù)游戲,很復(fù)雜,要求語(yǔ)言C++??,還可以通過C語(yǔ)言程序設(shè)計(jì)猜數(shù)游戲,VB

科技時(shí)代到來,優(yōu)異也隨之而來,我們會(huì)去關(guān)注C語(yǔ)言程序設(shè)計(jì)猜數(shù)游戲,VB程序設(shè)計(jì)中怎么設(shè)計(jì)猜數(shù)游戲???!!!,c語(yǔ)言課程設(shè)計(jì)-猜數(shù)游戲,設(shè)計(jì)一個(gè)猜數(shù)游戲,很復(fù)雜,要求語(yǔ)言C++??,還可以通過C語(yǔ)言程序設(shè)計(jì)猜數(shù)游戲,VB程序設(shè)計(jì)中怎么設(shè)計(jì)猜數(shù)游戲???!!!,c語(yǔ)言課程設(shè)計(jì)-猜數(shù)游戲,設(shè)計(jì)一個(gè)猜數(shù)游戲,很復(fù)雜,要求語(yǔ)言C++??進(jìn)一步去來了解,接下來就跟隨作者一起去看看吧!

1.C語(yǔ)言程序設(shè)計(jì)猜數(shù)游戲

我把思路寫下來吧。首先你可以用random()生成個(gè)隨機(jī)數(shù)放到int i中。聲明計(jì)數(shù)n,n=0。然后輸入一個(gè)數(shù)input,用while循環(huán)來控制,條件是1.循環(huán)里面可以去判斷if(input>i) 提示:Your answer is HIGH,try again,scanf("%d",&input);n++;continue; if(input7&&n<15) 提示:。。。;else exit(0)}差不多給你寫完了,再不會(huì)就沒辦法了,我這里也沒有c運(yùn)行環(huán)境

2.VB程序設(shè)計(jì)中怎么設(shè)計(jì)猜數(shù)游戲???!!!

天啊 你再加個(gè)判斷就可以啊 你是真的不會(huì)寫 還是懶得寫啊 把下面的代碼拷貝過去 自己運(yùn)行一下就知道怎么加這些限制 其實(shí)就加一個(gè)不可重復(fù)輸入數(shù)字和猜的字?jǐn)?shù)就可以了 把我的s和e 改成你的a和b就符合你的要求了 ---自己稍微改一點(diǎn)點(diǎn)Private Function getSerial(ByVal iLen As Integer, Optional ByVal bRepeat As Boolean = False) As StringIf iLen < 1 And iLen > 9 Then Exit IfDim iRnd As iCount As bExist As sSerial As iRnd = Int(Rnd(Now) * 9) If Not bRepeat Then For iCount = 1 To Len(sSerial) If iRnd = Val(Mid(sSerial, iCount, 1)) Then bExist = True Exit For Else bExist = False End If Next End If If Not bExist Then sSerial = iRnd & sSerial End IfLoop While Len(sSerial) < iLen'Debug. = Function (bEqual As Boolean, ByVal inString As String, ByVal cmpString As String) As StringDim iCount As jCount As iSame As iExist As iCount = 1 To Len(cmpString) For jCount = 1 To Len(inString) If Mid(cmpString, iCount, 1) = Mid(inString, jCount, 1) Then If jCount = iCount Then iSame = iSame + 1 Else iExist = iExist + 1 End If End If iSame = Len(cmpString) Then = "OK.." bEqual = TrueElse = iSame & "S" & iExist & "E " & inString bEqual = FalseEnd IfEnd Sub Command1_Click()'Debug.Print serial(8, True)Dim b As .Print (b, Text1.Text, Text2.Text)If b Then Command1.Enabled = False Text2.Visible = TrueEnd IfEnd Sub Command2_Click()Picture1.ClsText1.Text = ""Text2.Text = getSerial(5)Text2.Locked = TrueText2.Visible = .Enabled = TrueEnd Sub

3.c語(yǔ)言課程設(shè)計(jì)-猜數(shù)游戲

以下程序的功能是隨機(jī)產(chǎn)生數(shù)字,要求用戶猜測(cè)程序中產(chǎn)生的隨機(jī)數(shù)字,并輸入,根據(jù)猜測(cè)的結(jié)果程序給出不同的響應(yīng),如果15次沒猜對(duì)則退出。 源程序如下: #include #include #include main() { int count;/*猜數(shù)字的次數(shù)*/ int number;/*系統(tǒng)產(chǎn)生的隨機(jī)數(shù)字*/ int guess;/*程序員輸入數(shù)字*/ char yes='Y'; clrscr(); printf("\nNow let us play the game.\n Guess the number:"); while (toupper(yes)=='Y') { count=0; randomize(); number=random(100)+1; do { do { printf("\nInput an integer number(1~100):"); scanf("%d",&guess); }while(!(guess>=1&&guess<=100));/*結(jié)束第二層DO~WHILE循環(huán)*/ if (guessnumber) printf("\n Your answer is high,try again!");/*如果用戶輸入的數(shù)字大于系統(tǒng)隨機(jī)數(shù),則輸出數(shù)字太小的提示信息*/ count++;/*猜測(cè)次數(shù)加一*/ if (count==15) { printf("\n This is the %d times! Think it hard next!",count); exit(0);/*如猜測(cè)15次還沒猜對(duì),則退出游戲*/ } }while (!(guess==number)); if (count<=7)/*猜測(cè)的次數(shù)小于7次*/ { printf("\n You have got it in %d times.\n",count); printf("\n you guess right,!");/*游戲成功則提示祝賀信息*/ } else { printf("\n You got it in %d times.\n",count); printf("\n I bet you can do it better!");/*游戲失敗則提示鼓勵(lì)信息*/ } printf("\n NEXT?(Y/N):");/*選擇是否重新游戲*/ scanf("%c",&yes); } } 運(yùn)行程序時(shí)請(qǐng)用戶猜數(shù)字,該數(shù)字由系統(tǒng)隨機(jī)產(chǎn)生,用戶最多有七次猜測(cè)的機(jī)會(huì),如果在七次內(nèi)猜對(duì)數(shù)字,則程序顯示祝賀信息,如果用戶大于七次猜對(duì)數(shù)字,則程序顯示鼓勵(lì)信息,如果用戶連續(xù)15次都沒有猜對(duì)數(shù)字,則游戲自動(dòng)退出。結(jié)束一次游戲后,系統(tǒng)詢問用戶進(jìn)行下一次猜數(shù)字游戲,用戶輸入“Y”則開始下一次猜數(shù)字游戲,用戶如果輸入“N”則退出游戲。 唉,花了個(gè)把小時(shí)終于搞出來了,應(yīng)可以看懂吧,程序中作了很詳細(xì)的解釋,且在*也作了功能說明! 如果認(rèn)為好的話,追加分?jǐn)?shù)哦!

4.設(shè)計(jì)一個(gè)猜數(shù)游戲,很復(fù)雜,要求語(yǔ)言C++

給個(gè)Fibonacci數(shù)列,固定兩個(gè)數(shù)的,其他的你可以參考了:#include #define N 8#define M 13int fib(int n){ int a = 0, b = 1, c; int i; if (0 == n) return 0; for (i = 0; i < n; i++) { c = b; b += a; a = c; } return b;}void main(){ int i = 0; while (1) { if (fib(i) == N && fib(i + 1) ==M) { printf("%d \n", fib(i + 2)); break; } i++; }}

上文講述了C語(yǔ)言程序設(shè)計(jì)猜數(shù)游戲,VB程序設(shè)計(jì)中怎么設(shè)計(jì)猜數(shù)游戲???!!!,c語(yǔ)言課程設(shè)計(jì)-猜數(shù)游戲,設(shè)計(jì)一個(gè)猜數(shù)游戲,很復(fù)雜,要求語(yǔ)言C++??,大致對(duì)C語(yǔ)言程序設(shè)計(jì)猜數(shù)游戲,VB程序設(shè)計(jì)中怎么設(shè)計(jì)猜數(shù)游戲???!!!,c語(yǔ)言課程設(shè)計(jì)-猜數(shù)游戲,設(shè)計(jì)一個(gè)猜數(shù)游戲,很復(fù)雜,要求語(yǔ)言C++??有個(gè)簡(jiǎn)單了解,如還需深了解請(qǐng)聯(lián)系作者。

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